# Чтобы найти сумму двух чисел без использования оператора

Опубликовано: 21 Января, 2022

Напишите программу для нахождения суммы положительных целых чисел без использования оператора. Разрешено только использование printf (). Никакие другие библиотечные функции использовать нельзя.

Solution
It’s a trick question. We can use printf() to find sum of two numbers as printf() returns the number of characters printed. The width field in printf() can be used to find the sum of two numbers. We can use ‘*’ which indicates the minimum width of output. For example, in the statement “printf(“%*d”, width, num);”, the specified ‘width’ is substituted in place of *, and ‘num’ is printed within the minimum width specified. If number of digits in ‘num’ is smaller than the specified ‘width’, the output is padded with blank spaces. If number of digits are more, the output is printed as it is (not truncated). In the following program, add() returns sum of x and y. It prints 2 spaces within the width specified using x and y. So total characters printed is equal to sum of x and y. That is why add() returns x+y.

## C++

 #include using namespace std;  int add(int x, int y){    return printf("%*c%*c", x, " ", y, " ");} // Driver codeint main(){    printf("Sum = %d", add(3, 4));    return 0;} // This code is contributed by shubhamsingh10

## C

 #include  int add(int x, int y){    return printf("%*c%*c", x, " ", y, " ");} // Driver codeint main(){    printf("Sum = %d", add(3, 4));    return 0;}

Выход:

Сумма = 7

The output is seven spaces followed by “Sum = 7”. We can avoid the leading spaces by using carriage return. Thanks to krazyCoder and Sandeep for suggesting this. The following program prints output without any leading spaces.

## C++

 #include using namespace std; int add(int x, int y){    return printf("%*c%*c", x, " ", y, " ");} // Driver codeint main(){    printf("Sum = %d", add(3, 4));    return 0;} // This code is contributed by shubhamsingh10

## C

 #include  int add(int x, int y){    return printf("%*c%*c", x, " ", y, " ");} // Driver codeint main(){    printf("Sum = %d", add(3, 4));    return 0;}

Выход:

Sum = 7

Another Method :

## C++

 #include using namespace std; int main(){    int a = 10, b = 5;    if (b > 0) {        while (b > 0) {            a++;            b--;        }    }    if (b < 0) { // when "b" is negative        while (b < 0) {            a--;            b++;        }    }    cout << "Sum = " << a;    return 0;} // This code is contributed by SHUBHAMSINGH10// This code is improved & fixed by Abhijeet Soni.

## C

 #include  int main(){    int a = 10, b = 5;    if (b > 0) {        while (b > 0) {            a++;            b--;        }    }    if (b < 0) { // when "b" is negative        while (b < 0) {            a--;            b++;        }    }    printf("Sum = %d", a);    return 0;} // This code is contributed by Abhijeet Soni

## Java

 // Java codeclass GfG {     public static void main(String[] args)    {        int a = 10, b = 5;        if (b > 0) {            while (b > 0) {                a++;                b--;            }        }        if (b < 0) { // when "b" is negative            while (b < 0) {                a--;                b++;            }        }        System.out.println("Sum is: " + a);    }} // This code is contributed by Abhijeet Soni

## Python3

 # Python 3 Code if __name__ == "__main__":         a = 10    b = 5     if b > 0:        while b > 0:            a = a + 1            b = b - 1    if b < 0:        while b < 0:            a = a - 1            b = b + 1         print("Sum is: ", a) # This code is contributed by Akanksha Rai# This code is improved & fixed by Abhijeet Soni

## C#

 // C# codeusing System; class GFG {    static public void Main()    {        int a = 10, b = 5;        if (b > 0) {            while (b > 0) {                a++;                b--;            }        }        if (b < 0) { // when "b" is negative            while (b < 0) {                a--;                b++;            }        }        Console.Write("Sum is: " + a);    }} // This code is contributed by Tushil// This code is improved & fixed by Abhijeet Soni.

## PHP

 0) {while(\$b > 0){    \$a++;    \$b--;}} if (\$b < 0) {while(\$b < 0){    \$a--;    \$b++;}}  echo "Sum is: ", \$a; // This code is contributed by Dinesh// This code is improved & fixed by Abhijeet Soni.?>

## Javascript



Выход:

сумма = 15

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