Экспоненциальный поиск

Опубликовано: 20 Января, 2022

Название этого алгоритма поиска может вводить в заблуждение, поскольку он работает за время O (Log n). Название происходит от способа поиска элемента.

 Учитывая отсортированный массив и элемент x, который должен быть 
поиск, найти позицию x в массиве.

Ввод: arr [] = {10, 20, 40, 45, 55}
        х = 45
Выход: элемент найден с индексом 3

Ввод: arr [] = {10, 15, 25, 45, 55}
        х = 15
Выход: элемент найден с индексом 1
Рекомендуется: сначала попробуйте свой подход в {IDE}, прежде чем переходить к решению.

Мы обсудили линейный поиск, бинарный поиск для этой проблемы.
Экспоненциальный поиск состоит из двух этапов:

  1. Найдите диапазон, в котором присутствует элемент
  2. Выполните двоичный поиск в указанном выше диапазоне.

How to find the range where element may be present? 
The idea is to start with subarray size 1, compare its last element with x, then try size 2, then 4 and so on until last element of a subarray is not greater. 
Once we find an index i (after repeated doubling of i), we know that the element must be present between i/2 and i (Why i/2? because we could not find a greater value in previous iteration)
Given below are the implementations of above steps.

C++

// C++ program to find an element x in a
// sorted array using Exponential search.
#include <bits/stdc++.h>
using namespace std;
 
int binarySearch(int arr[], int, int, int);
 
// Returns position of first occurrence of
// x in array
int exponentialSearch(int arr[], int n, int x)
{
    // If x is present at firt location itself
    if (arr[0] == x)
        return 0;
 
    // Find range for binary search by
    // repeated doubling
    int i = 1;
    while (i < n && arr[i] <= x)
        i = i*2;
 
    //  Call binary search for the found range.
    return binarySearch(arr, i/2,
                            min(i, n-1), x);
}
 
// A recursive binary search function. It returns
// location of x in  given array arr[l..r] is
// present, otherwise -1
int binarySearch(int arr[], int l, int r, int x)
{
    if (r >= l)
    {
        int mid = l + (r - l)/2;
 
        // If the element is present at the middle
        // itself
        if (arr[mid] == x)
            return mid;
 
        // If element is smaller than mid, then it
        // can only be present n left subarray
        if (arr[mid] > x)
            return binarySearch(arr, l, mid-1, x);
 
        // Else the element can only be present
        // in right subarray
        return binarySearch(arr, mid+1, r, x);
    }
 
    // We reach here when element is not present
    // in array
    return -1;
}
 
// Driver code
int main(void)
{
   int arr[] = {2, 3, 4, 10, 40};
   int n = sizeof(arr)/ sizeof(arr[0]);
   int x = 10;
   int result = exponentialSearch(arr, n, x);
   (result == -1)? printf("Element is not
                            present in array")
                 : printf("Element is present
                                 at index %d",
                                       result);
   return 0;
}

Java

// Java program to
// find an element x in a
// sorted array using
// Exponential search.
import java.util.Arrays;
 
class GFG
{
    // Returns position of
    // first occurrence of
    // x in array
    static int exponentialSearch(int arr[],
                                 int n, int x)
    {
        // If x is present at firt location itself
        if (arr[0] == x)
            return 0;
     
        // Find range for binary search by
        // repeated doubling
        int i = 1;
        while (i < n && arr[i] <= x)
            i = i*2;
     
        // Call binary search for the found range.
        return Arrays.binarySearch(arr, i/2,
                              Math.min(i, n-1), x);
    }
     
    // Driver code
    public static void main(String args[])
    {
        int arr[] = {2, 3, 4, 10, 40};
        int x = 10;
        int result = exponentialSearch(arr,
                                  arr.length, x);
         
        System.out.println((result < 0) ?
          "Element is not present in array" :
          "Element is present at index " +
                             result);
    }
}

Python

# Python program to find an element x
# in a sorted array using Exponential Search
 
# A recurssive binary search function returns
# location  of x in given array arr[l..r] is
# present, otherwise -1
def binarySearch( arr, l, r, x):
    if r >= l:
        mid = l + ( r-l ) / 2
         
        # If the element is present at
        # the middle itself
        if arr[mid] == x:
            return mid
         
        # If the element is smaller than mid,
        # then it can only be present in the
        # left subarray
        if arr[mid] > x:
            return binarySearch(arr, l,
                                mid - 1, x)
         
        # Else he element can only be
        # present in the right
        return binarySearch(arr, mid + 1, r, x)
         
    # We reach here if the element is not present
    return -1
 
# Returns the position of first
# occurrence of x in array
def exponentialSearch(arr, n, x):
    # IF x is present at first
    # location itself
    if arr[0] == x:
        return 0
         
    # Find range for binary search
    # j by repeated doubling
    i = 1
    while i < n and arr[i] <= x:
        i = i * 2
     
    # Call binary search for the found range
    return binarySearch( arr, i / 2,
                         min(i, n-1), x)
     
 
# Driver Code
arr = [2, 3, 4, 10, 40]
n = len(arr)
x = 10
result = exponentialSearch(arr, n, x)
if result == -1:
    print "Element not found in thye array"
else:
    print "Element is present at index %d" %(result)
 
# This code is contributed by Harshit Agrawal

C#

// C# program to find an element x in a
// sorted array using Exponential search.
using System;
class GFG {
 
// Returns position of first
// occurrence of x in array
static int exponentialSearch(int []arr,
                         int n, int x)
{
     
    // If x is present at
    // first location itself
    if (arr[0] == x)
        return 0;
 
    // Find range for binary search
    // by repeated doubling
    int i = 1;
    while (i < n && arr[i] <= x)
        i = i * 2;
 
    // Call binary search for
    // the found range.
    return binarySearch(arr, i/2,
                       Math.Min(i, n - 1), x);
}
 
// A recursive binary search
// function. It returns location
// of x in given array arr[l..r] is
// present, otherwise -1
static int binarySearch(int []arr, int l,
                        int r, int x)
{
    if (r >= l)
    {
        int mid = l + (r - l) / 2;
 
        // If the element is present
        // at the middle itself
        if (arr[mid] == x)
            return mid;
 
        // If element is smaller than
        // mid, then it can only be
        // present n left subarray
        if (arr[mid] > x)
            return binarySearch(arr, l, mid - 1, x);
 
        // Else the element can only
        // be present in right subarray
        return binarySearch(arr, mid + 1, r, x);
    }
 
    // We reach here when element
    // is not present in array
    return -1;
}
 
// Driver code
public static void Main()
{
    int []arr = {2, 3, 4, 10, 40};
    int n = arr.Length;
    int x = 10;
    int result = exponentialSearch(arr, n, x);
    if (result == -1)
            Console.Write("Element is not
                          present in array");
        else
            Console.Write("Element is
                           present at index "
                                   + result);
}
}
 
// This code is contributed by Smitha

PHP

<?php
// PHP program to find an element x in a
// sorted array using Exponential search.
 
// Returns position of first
// occurrence of x in array
function exponentialSearch($arr, $n, $x)
{
     
    // If x is present at
    // first location itself
    if ($arr[0] == $x)
        return 0;
 
    // Find range for binary search
    // by repeated doubling
    $i = 1;
    while ($i< $n and $arr[$i] <=$x)
        $i = $i * 2;
 
    // Call binary search
    // for the found range.
    return binarySearch($arr, $i / 2,
                        min($i, $n - 1), $x);
}
 
// A recursive binary search
// function. It returns location
// of x in given array arr[l..r] is
// present, otherwise -1
function binarySearch($arr, $l,
                      $r, $x)
{
    if ($r >= $l)
    {
        $mid = $l + ($r - $l)/2;
 
        // If the element is
        // present at the middle
        // itself
        if ($arr[$mid] == $x)
            return $mid;
 
        // If element is smaller
        // than mid, then it
        // can only be present
        // n left subarray
        if ($arr[$mid] > $x)
            return binarySearch($arr, $l,
                                $mid - 1, $x);
 
        // Else the element
        // can only be present
        // in right subarray
        return binarySearch($arr, $mid + 1,
                                    $r, $x);
    }
 
    // We reach here when
    // element is not present
    // in array
    return -1;
}
 
// Driver code
$arr = array(2, 3, 4, 10, 40);
$n = count($arr);
$x = 10;
$result = exponentialSearch($arr, $n, $x);
if($result == -1)
    echo "Element is not present in array";
else
    echo "Element is present at index ",
                                $result;
 
// This code is contributed by anuj_67
?>

Javascript

<script>
 
// Javascript program to find an element x
// in a sorted array using Exponential Search
  
// A recursive binary search
// function. It returns location
// of x in given array arr[l..r] is
// present, otherwise -1
function binarySearch(arr, l, r, x)
{
    if (r >= l)
    {
        let mid = l + (r - l) / 2;
  
        // If the element is present
        // at the middle itself
        if (arr[mid] == x)
            return mid;
  
        // If element is smaller than
        // mid, then it can only be
        // present n left subarray
        if (arr[mid] > x)
            return binarySearch(arr, l, mid - 1, x);
  
        // Else the element can only
        // be present in right subarray
        return binarySearch(arr, mid + 1, r, x);
    }
  
    // We reach here when element
    // is not present in array
    return -1;
}
 
 // Returns position of first
// occurrence of x in array
function exponentialSearch(arr, n, x)
{
      
    // If x is present at
    // first locati

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