Python | Панды TimedeltaIndex.difference

Опубликовано: 28 Марта, 2022

Python - отличный язык для анализа данных, в первую очередь из-за фантастической экосистемы пакетов Python, ориентированных на данные. Pandas - один из таких пакетов, который значительно упрощает импорт и анализ данных.

Pandas TimedeltaIndex.difference() function return a new Index with elements from the index that are not in other. This is the set difference of two Index objects. It’s sorted if sorting is possible.

Syntax : TimedeltaIndex.difference(other)

Parameters :
other : Index or array-like

Return : difference : Index

Example #1: Use TimedeltaIndex.difference() function to find the set difference of two TimedeltaIndex objects.

# importing pandas as pd
import pandas as pd
  
# Create the first TimedeltaIndex object
tidx1 = pd.TimedeltaIndex(data =["06:05:01.000030", "+23:59:59.999999"
                                 "22 day 2 min 3us 10ns", "+23:29:59.999999"
                                                         "+12:19:59.999999"])
  
# Create the seccond TimedeltaIndex object
tidx2 = pd.TimedeltaIndex(data =["09:11:18.000030", "+23:59:59.999999",
                                 "9 day 18 min 3us ", "+23:29:59.999999",
                                                     "+12:19:59.999999"])
  
# Print the first and second TimedeltaIndex object
print(tidx1, " ", tidx2)

Выход :

Now we will use the TimedeltaIndex.difference() function to find the set difference.

# find the set difference
tidx1.difference(tidx2)

Output :

As we can see in the output, the TimedeltaIndex.difference() function has returned a new object which contains only those elements which are unique to tidx1.
 
Example #2: Use TimedeltaIndex.difference() function to find the set difference of two TimedeltaIndex objects.

# importing pandas as pd
import pandas as pd
  
# Create the first TimedeltaIndex object
tidx1 = pd.TimedeltaIndex(start ="1 days 02:00:12.001124", periods = 5,
                                              freq ="D", name ="Koala")
  
# Create the second TimedeltaIndex object
tidx2 = pd.TimedeltaIndex(start ="3 days 02:00:12.001124", periods = 5,
                                              freq ="D", name ="Koala")
  
# Print the first and second TimedeltaIndex object
print(tidx1, " ", tidx2)

Output :


Now we will use the TimedeltaIndex.difference() function to find the set difference.

# find the set difference
tidx1.difference(tidx2)

Output :

As we can see in the output, the TimedeltaIndex.difference() function has returned a new object which contains only those elements which are unique to tidx1.

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