Класс 11 RD Sharma Solutions — Глава 29 Ограничения — Упражнение 29.10 | Набор 1
Оцените следующие ограничения:
Вопрос 1. 
Решение:
We have,
=
=
=
=
=
=
We know,
. So, we have,
= 4 log 5
Вопрос 2. 
Решение:
We have,
=
=
We know,
. So, we have,
=
As
, we get,
=
Вопрос 3. 
Решение:
We have,
=
=
=
As
, we get,
=
= (loge a)2
Вопрос 4.
, п≠0
Решение:
We have,
=
=
As
, we get,
=
=
Вопрос 5. 
Решение:
We have,
=
=
=
=
As
, we get,
= log a + log b
= log (ab)
Вопрос 6. 
Решение:
We have,
=
=
=
=
=
=
As
, we get,
= (log 3 − log 2)2
=
Вопрос 7. 
Решение:
We have,
=
=
=
=
As
, we get,
= 2(log2)2
Вопрос 8. 
Решение:
We have,
=
=
=
=
As
, we get,
= m log a − n log b
= log am − log bn
=
Вопрос 9. 
Решение:
We have,
=
=
=
As
, we get,
= log a + log b + log c
= log (abc)
Вопрос 10. 
Решение:
We have,
=
Let x − 2 = h. So, we get,
=
=
=
=
We know,
. So, we have,
= log a
Вопрос 11. 
Решение:
We have,
=
=
=
As
, we get,
= log 5 + log 3 + log 2
= log (5×3×2)
= log 30
Вопрос 12. 
Решение:
We have,
=
Let 1/x = h. We get,
=
=
As
, we get,
= log a
Вопрос 13. 
Решение:
We have,
=
=
=
=
=
=
As
and
, we get,
=
=
=
Вопрос 14. 
Решение:
We have,
=
=
=
As
, we get,
= log a + log b − log c − log d
= log a+ log b − (log c + log d)
= log ab − log cd
=
Вопрос 15. 
Решение:
We have,
=
=
As
and
, we get,
= log e + 1
= 1 + 1
= 2





. So, we have,
. So, we have,






























. So, we have,








, we get,





